\(\int \frac {\arccos (a x)}{x} \, dx\) [6]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [F]
   Sympy [F]
   Maxima [F]
   Giac [F]
   Mupad [F(-1)]

Optimal result

Integrand size = 8, antiderivative size = 51 \[ \int \frac {\arccos (a x)}{x} \, dx=-\frac {1}{2} i \arccos (a x)^2+\arccos (a x) \log \left (1+e^{2 i \arccos (a x)}\right )-\frac {1}{2} i \operatorname {PolyLog}\left (2,-e^{2 i \arccos (a x)}\right ) \]

[Out]

-1/2*I*arccos(a*x)^2+arccos(a*x)*ln(1+(a*x+I*(-a^2*x^2+1)^(1/2))^2)-1/2*I*polylog(2,-(a*x+I*(-a^2*x^2+1)^(1/2)
)^2)

Rubi [A] (verified)

Time = 0.04 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.625, Rules used = {4722, 3800, 2221, 2317, 2438} \[ \int \frac {\arccos (a x)}{x} \, dx=-\frac {1}{2} i \operatorname {PolyLog}\left (2,-e^{2 i \arccos (a x)}\right )-\frac {1}{2} i \arccos (a x)^2+\arccos (a x) \log \left (1+e^{2 i \arccos (a x)}\right ) \]

[In]

Int[ArcCos[a*x]/x,x]

[Out]

(-1/2*I)*ArcCos[a*x]^2 + ArcCos[a*x]*Log[1 + E^((2*I)*ArcCos[a*x])] - (I/2)*PolyLog[2, -E^((2*I)*ArcCos[a*x])]

Rule 2221

Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/((a_) + (b_.)*((F_)^((g_.)*((e_.) +
 (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp[((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x]
 - Dist[d*(m/(b*f*g*n*Log[F])), Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x], x] /; FreeQ[{F,
a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]

Rule 2317

Int[Log[(a_) + (b_.)*((F_)^((e_.)*((c_.) + (d_.)*(x_))))^(n_.)], x_Symbol] :> Dist[1/(d*e*n*Log[F]), Subst[Int
[Log[a + b*x]/x, x], x, (F^(e*(c + d*x)))^n], x] /; FreeQ[{F, a, b, c, d, e, n}, x] && GtQ[a, 0]

Rule 2438

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> Simp[-PolyLog[2, (-c)*e*x^n]/n, x] /; FreeQ[{c, d,
 e, n}, x] && EqQ[c*d, 1]

Rule 3800

Int[((c_.) + (d_.)*(x_))^(m_.)*tan[(e_.) + (f_.)*(x_)], x_Symbol] :> Simp[I*((c + d*x)^(m + 1)/(d*(m + 1))), x
] - Dist[2*I, Int[(c + d*x)^m*(E^(2*I*(e + f*x))/(1 + E^(2*I*(e + f*x)))), x], x] /; FreeQ[{c, d, e, f}, x] &&
 IGtQ[m, 0]

Rule 4722

Int[((a_.) + ArcCos[(c_.)*(x_)]*(b_.))^(n_.)/(x_), x_Symbol] :> -Subst[Int[(a + b*x)^n*Tan[x], x], x, ArcCos[c
*x]] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0]

Rubi steps \begin{align*} \text {integral}& = -\text {Subst}(\int x \tan (x) \, dx,x,\arccos (a x)) \\ & = -\frac {1}{2} i \arccos (a x)^2+2 i \text {Subst}\left (\int \frac {e^{2 i x} x}{1+e^{2 i x}} \, dx,x,\arccos (a x)\right ) \\ & = -\frac {1}{2} i \arccos (a x)^2+\arccos (a x) \log \left (1+e^{2 i \arccos (a x)}\right )-\text {Subst}\left (\int \log \left (1+e^{2 i x}\right ) \, dx,x,\arccos (a x)\right ) \\ & = -\frac {1}{2} i \arccos (a x)^2+\arccos (a x) \log \left (1+e^{2 i \arccos (a x)}\right )+\frac {1}{2} i \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 i \arccos (a x)}\right ) \\ & = -\frac {1}{2} i \arccos (a x)^2+\arccos (a x) \log \left (1+e^{2 i \arccos (a x)}\right )-\frac {1}{2} i \operatorname {PolyLog}\left (2,-e^{2 i \arccos (a x)}\right ) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.00 \[ \int \frac {\arccos (a x)}{x} \, dx=-\frac {1}{2} i \arccos (a x)^2+\arccos (a x) \log \left (1+e^{2 i \arccos (a x)}\right )-\frac {1}{2} i \operatorname {PolyLog}\left (2,-e^{2 i \arccos (a x)}\right ) \]

[In]

Integrate[ArcCos[a*x]/x,x]

[Out]

(-1/2*I)*ArcCos[a*x]^2 + ArcCos[a*x]*Log[1 + E^((2*I)*ArcCos[a*x])] - (I/2)*PolyLog[2, -E^((2*I)*ArcCos[a*x])]

Maple [A] (verified)

Time = 0.71 (sec) , antiderivative size = 68, normalized size of antiderivative = 1.33

method result size
derivativedivides \(-\frac {i \arccos \left (a x \right )^{2}}{2}+\arccos \left (a x \right ) \ln \left (1+\left (i \sqrt {-a^{2} x^{2}+1}+a x \right )^{2}\right )-\frac {i \operatorname {polylog}\left (2, -\left (i \sqrt {-a^{2} x^{2}+1}+a x \right )^{2}\right )}{2}\) \(68\)
default \(-\frac {i \arccos \left (a x \right )^{2}}{2}+\arccos \left (a x \right ) \ln \left (1+\left (i \sqrt {-a^{2} x^{2}+1}+a x \right )^{2}\right )-\frac {i \operatorname {polylog}\left (2, -\left (i \sqrt {-a^{2} x^{2}+1}+a x \right )^{2}\right )}{2}\) \(68\)

[In]

int(arccos(a*x)/x,x,method=_RETURNVERBOSE)

[Out]

-1/2*I*arccos(a*x)^2+arccos(a*x)*ln(1+(I*(-a^2*x^2+1)^(1/2)+a*x)^2)-1/2*I*polylog(2,-(I*(-a^2*x^2+1)^(1/2)+a*x
)^2)

Fricas [F]

\[ \int \frac {\arccos (a x)}{x} \, dx=\int { \frac {\arccos \left (a x\right )}{x} \,d x } \]

[In]

integrate(arccos(a*x)/x,x, algorithm="fricas")

[Out]

integral(arccos(a*x)/x, x)

Sympy [F]

\[ \int \frac {\arccos (a x)}{x} \, dx=\int \frac {\operatorname {acos}{\left (a x \right )}}{x}\, dx \]

[In]

integrate(acos(a*x)/x,x)

[Out]

Integral(acos(a*x)/x, x)

Maxima [F]

\[ \int \frac {\arccos (a x)}{x} \, dx=\int { \frac {\arccos \left (a x\right )}{x} \,d x } \]

[In]

integrate(arccos(a*x)/x,x, algorithm="maxima")

[Out]

integrate(arccos(a*x)/x, x)

Giac [F]

\[ \int \frac {\arccos (a x)}{x} \, dx=\int { \frac {\arccos \left (a x\right )}{x} \,d x } \]

[In]

integrate(arccos(a*x)/x,x, algorithm="giac")

[Out]

integrate(arccos(a*x)/x, x)

Mupad [F(-1)]

Timed out. \[ \int \frac {\arccos (a x)}{x} \, dx=\int \frac {\mathrm {acos}\left (a\,x\right )}{x} \,d x \]

[In]

int(acos(a*x)/x,x)

[Out]

int(acos(a*x)/x, x)